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The Monthly Income of a Group of 320 Employee in a Company is Given Below - Mathematics

Sum

The monthly income of a group of 320 employee in a company is given below 

Monthly income (thousands)  No.of employee 
6-7 20
7-8 45
8-9 65
9-10 95
10-11 60
11-12 30
12-13 5

Draw an ogive of the distribution on a graph paper taking 2 cm = rS 1000 on one axis and 2 cm = 50 employee on the other axis. From the graph detemine: 

(1) the median wage. 

(2) number of employee whose income is below Rs 8500 

(3) If salary of a senior employee is above Rs11,500 find the number of senior employee  in the company. 

(4) the upper quartile.

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Solution

Monthly income (thousands)  No.of employee (f) Cumulative frequency 
6-7 20 20
7-8 45 65
8-9 65 130
9-10 95 225
10-11 60 285
11-12 30 315
12-13 5 320
Total 320  

Number of employees = 320 

Median`=320/2=160^("th")` term 

Though marks 160. draw a parallel line to x-axis which the curve at A draw a perpendicular to x-axis  meeting it at B the value of point B is the median = Rs 9.3 thousands 

The number of employees whit income below Rs 8500 = 95 (approx from the graph ) 

Number of employee with income below Rs 115 - 305 (approx from the graph ) 

Therefore number of employee with income (senior employees) = 320 - 305 = 15 

Upper quartile = `Q_3=320xx3/4=240^"th"` term = 10.3 thousands = Rs,10,300 

  Is there an error in this question or solution?
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APPEARS IN

Selina Concise Maths Class 10 ICSE
Chapter 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (E) | Q 11 | Page 376
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