Advertisement Remove all ads

The Moment of Inertia of a Uniform Rod of Mass 0⋅50 Kg and Length 1 M is 0⋅10 Kg-m2 About a Line Perpendicular to the Rod. Find the Distance of this Line from the Middle Point of the Rod. - Physics

Sum

The moment of inertia of a uniform rod of mass 0⋅50 kg and length 1 m is 0⋅10 kg-m2about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

Advertisement Remove all ads

Solution

Given

Length of the rod, l = 1 m

Mass of the rod, m = 0.5 kg

Let the rod moves at a distance d from the centre.

On applying parallel axis theorem, we get

Moment of inertia about that axis,

\[I = \left( \frac{m l^2}{12} \right) + m d^2 = 0 . 10\]

\[I = \frac{0 . 5 \times l^2}{12} + 0 . 5 \times d^2 = 0 . 10\]

\[ \Rightarrow \frac{1}{12} + d^2 = 0 . 2\]

\[ \Rightarrow d^2 = 0 . 118\]

\[ \Rightarrow d = 0 . 342\text{ m from the centre}\]

Concept: Values of Moments of Inertia for Simple Geometrical Objects (No Derivation)
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 10 Rotational Mechanics
Q 12 | Page 196
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×