Question

The molar conductivity of a 0.5 mol dm⁻³ solution of AgNO₃ with electrolytic conductivity of 5.76 × 10⁻³ S cm⁻¹ at 298 K is ____________.

Options

• 2.88 S cm² mol⁻¹

• 11.52 S cm² mol⁻¹

• 0.086 S cm² mol⁻¹

• 28.8 S cm² mol⁻¹

Answer 1

The molar conductivity of a 0.5 mol dm⁻³ solution of AgNO₃ with electrolytic conductivity of 5.76 × 10⁻³ S cm⁻¹ at 298 K is 11.52 S cm² mol⁻¹.

Explanation:

Λ = `"κ"/"M" xx 10^-3  "mol"^-1  "m"^3`

= `(5.76 xx 10^-3 xx "S cm"^-1 xx 10^-3)/0.5` mol⁻¹ m³

= `(5.76 xx 10^-3 xx 10^-3 xx 10^6)/0.5` S cm⁻¹ mol⁻¹ cm³

= 11.52 S cm² mol⁻¹