Advertisement Remove all ads

The mid-points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to - Mathematics

MCQ

The mid-points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to

Options

  •  ar (ΔABC)

  • \[\frac{1}{2}\] ar (ΔABC)

     

  • \[\frac{1}{3}\] ar (ΔABC)

     

  • \[\frac{1}{4}\]  ar (ΔABC)

     

Advertisement Remove all ads

Solution

Given: (1) ABCD is a triangle.

(2) mid points of the sides of ΔABC with any of the vertices forms a parallelogram.

To find: Area of the parallelogram

Calculation: We know that: Area of a parallelogram = base × height

Hence area of ||gm DECF = EC × EG

area of ||gm DECF = EC × EG

area of ||gm DECF =`1/2 BC xx 1/2 AE` (E is the midpoint of BC)

area of ||gm DECF =`1/2(1/2BC xx AE)`

area of ||gm DECF = `1/2(ar ( ΔABC)) ` 

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 14 Areas of Parallelograms and Triangles
Q 19 | Page 62
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×