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The Mean of a Binomial Distribution is 10 and Its Standard Deviation is 2; Write the Value of Q. - Mathematics

ConceptBernoulli Trials and Binomial Distribution

Question

The mean of a binomial distribution is 10 and its standard deviation is 2; write the value of q.

Solution

$\text{ Mean of the binomial distribution, i . e . np } = 10$
$\text{ Variance } = \left( \text{ Standard deviation } \right)^2 ,\text{ i . e . npq } = 4$
$\therefore q = \frac{\text{ Variance } }{\text{ Mean} } = 0 . 4$

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Solution The Mean of a Binomial Distribution is 10 and Its Standard Deviation is 2; Write the Value of Q. Concept: Bernoulli Trials and Binomial Distribution.
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