The mass of a lead piece is 115 g. When it is immersed into a measuring cylinder, the water level rises from 20 ml mark to 30 ml mark. Find the volume of the lead piece .
Given , M = 115 g
`V_1` = 20 ml , `V_2` = 30 ml
(I) Volume of lead piece V = `V_2` - `V_1`
= 30 ml - 20 ml
= 10 ml or 10 `cm^3` [ ∴ 1 ml = 1 `cm^3`]