# The Magnetic Field in a Region is Given by → B = → K B 0 L Y Where L is a Fixed Length. a Conducting Rod of Length L Lies Along the Y-axis Between the Origin and the Point (0, L, 0). - Physics

Sum

The magnetic field in a region is given by $\overrightarrow{B} = \overrightarrow{k} \frac{B_0}{L}y$ where L is a fixed length. A conducting rod of length L lies along the Y-axis between the origin and the point (0, L, 0). If the rod moves with a velocity v = v$\overrightarrow{i},$ find the emf induced between the ends of the rod.

#### Solution

Magnetic field in the given region,

$\overrightarrow{B} = \frac{B_0}{L}y \hat k$

Length of the rod on the y-axis = L

Velocity of the rod, v = v$\hat i$

We will consider a small element of length dy on the rod.

Now,

Emf induced in the element:-

de = Bvdy

$\Rightarrow de = \frac{B_0}{L}y \times v_0 \times dy$

$= \frac{B_0 v_0}{L}ydy$

And,

$e = \frac{B_0 v_0}{L} \int\limits_0^L ydy$

$= \frac{B_0 v_0}{L} \left[ \frac{y^2}{2} \right]_0^L$

$= \frac{B_0 v_0}{L}\frac{L^2}{2}$

$= \frac{1}{2} B_0 v_0 L$

Concept: Induced Emf and Current
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 16 Electromagnetic Induction
Q 54 | Page 310