# The Magnetic Field B and the Magnetic Intensity H in a Material Are Found to Be 1.6 T and 1000 a M−1, Respectively. Calculate the Relative Permeability µR and the Susceptibility χ of the Material. - Physics

Sum

The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A m−1, respectively. Calculate the relative permeability µr and the susceptibility χ of the material.

#### Solution

Here,

Magnetic field strength, B = 1.6 T

Magnetising intensity in a material, H = 1000 A/m

The relation between magnetic field and magnetising field is given by

$\mu = \frac{B}{H}$

$\Rightarrow \mu = \frac{1 . 6}{1000}$

$\Rightarrow \mu = 1 . 6 \times {10}^{- 3}$

Relative permeability is defined as theratio of permeability in a medium to that in vacuum.

$\text{So, }\mu_r = \frac{\mu}{\mu_0} = \frac{1 . 6 \times {10}^{- 3}}{4\pi \times {10}^{- 7}}$

$\Rightarrow \mu_r = 0 . 127 \times {10}^4$

$\Rightarrow \mu_r = 1 . 3 \times {10}^3$

Relative permeability (mu_r) is given by,

$\mu_r = (1 + \chi)$

$\Rightarrow \chi = 1 . 3 \times {10}^3 - 1$

$\Rightarrow \chi = 1300 - 1$

$\Rightarrow \chi = 1299 = 1 . 299 \times {10}^3$

$\Rightarrow \chi \approx 1 . 3 \times {10}^3$

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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 15 Magnetic Properties of Matter
Q 6 | Page 286