Advertisement Remove all ads

The Longitudinal Waves Travel in a Coiled Spring at a Rate of 4 M/S. the Distance Between Two Consecutive Compressions is 20 Cm. Find : (I) Wavelength of the Wave (Ii) Frequency of the Wave - Science

Answer in Brief
Short Note

The longitudinal waves travel in a coiled spring at a rate of 4 m/s. The distance between two consecutive compressions is 20 cm. Find :
(i) Wavelength of the wave (ii) Frequency of the wave

Advertisement Remove all ads

Solution

The distance between two consecutive compressions or rare factions is equal to its wavelength.
Hence, from the diagram of wave we can say that wavelength is 0.2 m.

(ii) Now we have to calculate the frequency of the wave.
Given: Velocity ν = 4 m/s
Wavelength λ = 0.2 m
We know the relation between velocity, frequency, and wavelength `f = v/lambda` ,
where v is the velocity of sound , f the frequency , and `lambda` the wavelength . 
so ,
`f = 4/0.2` Hz
= 20 Hz
Therefore , frequency of the wave is 20 Hz .

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Lakhmir Singh Science Class 9 Physics
Chapter 5 Sound
Hots Questions | Q 85 | Page 188
Advertisement Remove all ads

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×