# The Light Emitted in the Transition N = 3 to N = 2 in Hydrogen is Called Hα Light. Find the Maximum Work Function a Metal - Physics

Sum

The light emitted in the transition n = 3 to n = 2 in hydrogen is called Hα light. Find the maximum work function a metal can have so that Hα light can emit photoelectrons from it.

#### Solution

The Hα light can emit the photoelectrons if its energy is greater than or equal to the work function of the metal.

Energy possessed by Hα light (E) is given by

E = 13.6 (1/n_1^2 - 1/n_2^2)eV

Here , n_1 = 2 , n_2 = 3

therefore E = 13.6 xx (1/4 - 1/4 )
= (13.6xx5)/36 = 1.89  eV
= 1.90 eV

Hα light will be able to emit electron from the metal surface for the maximum work function of metal to be 1.90 eV.

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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 21 Bohr’s Model and Physics of Atom
Q 38 | Page 385