The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is ______.
Options
9 cm
10 cm
8 cm
20 cm
Solution
The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is 10 cm.
Explanation:
We know that,
A rhombus is a simple quadrilateral whose four sides are of same length and diagonals are perpendicular bisector of each other.
We get,
AC = 16 cm and BD = 12 cm
∠AOB = 90°
∵ AC and BD bisects each other
AO = `1/2` AC and BO = `1/2` BD
Then we get,
AO = 8 cm and BO = 6 cm
Now, In right angled ∆AOB
Using the Pythagoras theorem,
We have,
AB2 = AO2 + OB2
AB2 = 82 + 62
= 64 + 36
= 100
∴ AB = `sqrt(100)` = 10 cm
We know that the four sides of a rhombus are equal.
Therefore, we get,
One side of rhombus = 10 cm.