#### Question

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes. [Use Π = 22/7]

#### Solution

We know that in 1 hour (i.e., 60 minutes), the minute hand rotates 360°.

In 5 minutes, minute hand will rotate = 360^@/60xx5 = 30^@

Therefore, the area swept by the minute hand in 5 minutes will be the area of a sector of 30° in a circle of 14 cm radius.

Area of sector of angle θ = `θ/(360°) xx pir^2`

Area of sector of 30° =`(30°)/(360°)xx22/7xx14xx14`

`=22/12xx2xx14`

`=(11xx14)/3`

=154/3 cm^{2}

Therefore, the area swept by the minute hand in 5 minutes is 154/3 cm^{2}

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Solution The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes. Concept: Areas of Sector and Segment of a Circle.