# The Kβ X-ray of Argon Has a Wavelength of 0.36 Nm. the Minimum Energy Needed to Ionize an Argon Atom is 16 Ev. Find the Energy Needed to Knock Out an Electron from the K Shell of an Argon Atom. - Physics

Sum

The Kβ X-ray of argon has a wavelength of 0.36 nm. The minimum energy needed to ionize an argon atom is 16 eV. Find the energy needed to knock out an electron from the K shell of an argon atom.

#### Solution

Given:-

Wavelength of Kβ X-ray of argon, λ = 0.36 nm

Energy needed to ionise an argon atom = 16 eV

Energy of Kβ X-ray of argon (E) is given by

E = 1242/0.36 = 3450  "eV"

Energy needed to knock out an electron from K shell

EK = (3450 + 16) eV

EK = 3466 eV ≈  3.47 keV

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