#### Question

The K_{β} X-ray of argon has a wavelength of 0.36 nm. The minimum energy needed to ionize an argon atom is 16 eV. Find the energy needed to knock out an electron from the K shell of an argon atom.

#### Solution

Given:-

Wavelength of K_{β} X-ray of argon, λ = 0.36 nm

Energy needed to ionise an argon atom = 16 eV

Energy of K_{β} X-ray of argon (E) is given by

`E = 1242/0.36 = 3450 "eV"`

Energy needed to knock out an electron from K shell

E_{K} = (3450 + 16) eV

E_{K} = 3466 eV ≈ 3.47 keV

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#### APPEARS IN

Solution The Kβ X-ray of Argon Has a Wavelength of 0.36 Nm. the Minimum Energy Needed to Ionize an Argon Atom is 16 Ev. Find the Energy Needed to Knock Out an Electron from the K Shell of an Argon Atom. Concept: Electromagnetic Spectrum.