Sum

The internal energy of a gas is given by U = 1.5 pV. It expands from 100 cm^{3} to 200 cm^{3}against a constant pressure of 1.0 × 10^{5} Pa. Calculate the heat absorbed by the gas in the process.

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#### Solution

Let change in volume of the gas be ∆V.

∆V = (200 − 100) cm^{3} = 100 cm^{3}

= 10^{−4} m^{3}

p = 1 × 10^{5} Pa

Change in internal energy of the system, ∆U = 1.5 pV

∆U = 1.5 × 10^{5} × 10^{−4} = 15 J

∆W = p∆V

= 10^{5} × 10^{−4} = 10 J

Using the first law of thermodynamics, we get

∆Q = ∆U + ∆W = 10 + 15 = 25 J

Thus, heat absorbed by the system is 25 J.

Concept: First Law of Thermodynamics

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