The Inner Diameter of a Cylindrical Wooden Pipe is 24 Cm and Its Outer Diameter is 28 Cm. the Length of the Pipe is 35 Cm. Find the Mass of the Pipe, If 1 Cm3 of Wood Has a Mass of 0.6 Gm. - Mathematics

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Answer in Brief

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3  of wood has a mass of 0.6 gm.

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Given data is as follows:

Inner diameter = 24cm

Outer diameter = 28cm

h = 35cm

Mass of 1 cm3 of wood = 0.6gm

We have to find the mass of the pipe.

In this problem the inner and outer diameter of the pipe is given. Let us first find out the radius.

Inner radius (r) = 12cm

Outer radius (R) = 14cm

Volume of the hollow pipe = `pi (R^2 - r^2 ) h`

`= 22/7 xx ( 14^2 - 12^2 ) xx 35 `

`= 22 xx 5 xx 2 xx 26`

` = 5720  cm ^3`

It is given that,

cm3 of wood weighs 0.6gm

Therefore, 5720  cm3  of wood will weigh  5720 × .6 = 3432gm

 = 3.432kg

Therefore, weight of the wooden pipe = 3.432kg

Concept: Surface Area of Cylinder
  Is there an error in this question or solution?


RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.2 | Q 3 | Page 21

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