# The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g. - Mathematics

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g.

["Assume "pi=22/7]

#### Solution

Inner radius (r1) of cylindrical pipe = (24/2)cm = 12 cm

Outer radius (r2) of cylindrical pipe = (28/2)cm = 14 cm

Height (h) of pipe = Length of pipe = 35 cm

"Volume of pipe "= pi(r_2^2-r_1^2)h

=[22/7xx(14^2-12^2)xx35]cm^3

= 110 x 52 cm3

= 5720 cm3

Mass of 1 cm3 wood = 0.6 g

Mass of 5720 cm3 wood = (5720 × 0.6) g

= 3432 g

= 3.432 kg

Concept: Volume of a Cylinder
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Chapter 13: Surface Area and Volumes - Exercise 13.6 [Page 230]

#### APPEARS IN

NCERT Class 9 Maths
Chapter 13 Surface Area and Volumes
Exercise 13.6 | Q 2 | Page 230

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