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The inner diameter of a circular well is 3.5 m. It is 10 m deep Find:

(i) inner curved surface area.

(ii) the cost of plastering this curved surface at the rate of Rs. `40 per m^2`

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#### Solution

Inner radius (r) of circular well=1.75m

Depth (n) of circular well =10m

(1) Inner curved surface area = `2pirh`

=`2xx22/7xx1.75xx10m^2`

=`(144xx0.25xx10)m^2`

=110m^2

(2) Cost of plastering `1m^2` area = Rs.40.

Cost of plastering `110m^2` area= Rs (100xx40)

=Rs.4400

Concept: Surface Area of Cylinder

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