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The Height of a Right Circular Cylinder is 10.5 M. Three Times the Sum of the Areas of Its Two Circular Faces is Twice the Area of the Curved Surface. Find the Volume of the Cylinder. - Mathematics

Sum

The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the area of the curved surface. Find the volume of the cylinder.

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Solution

Given data is as follows:

 h = 10.5 m 

`3(pir^2 + pir^2) = 2(2pirh)`

We have to find the volume of the cylinder.

From the given data, we have

`3(pir^2 + pir^2) = 2(2pirh)`

               `6pir^2 = 4pirh`

                  `3r = 2h`

But we know from the given data, that  h = 10.5 m

Therefore,

Since we know r and h , we can easily find the volume of the cylinder.

Volume =  `pir^2h`

=`22/7 xx 7 xx7 xx 10.5`

Volume = 1617 m3

Therefore, the volume of the cylinder is 1617 m3.

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.2 | Q 16 | Page 21
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