Maharashtra State BoardHSC Science (General) 11th
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The half-life of 24Na is 900 minutes. What is its decay constant? - Chemistry

Numerical

The half-life of 24Na is 900 minutes. What is its decay constant?

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Solution

Given: t1/2 = 900 minutes

To find: λ

Formula: `lambda = 0.693/"t"_(1//2)`

Calculation: `lambda = 0.693/"t"_(1//2) = 0.693/(900 min)`

λ = 7.7 × 10-4 min-1 

Decay constant for 24Na is 7.7 × 10-4 min-1.

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APPEARS IN

Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 13 Nuclear Chemistry and Radioactivity
Exercises | Q 3. (K) | Page 202
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