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# The Gravitational Force Acting on a Particle of 1 G Due to a Similar Particle is Equal to 6.67 × 10−17 N. Calculate the Separation Between the Particles. - Physics

Sum

The gravitational force acting on a particle of 1 g due to a similar particle is equal to 6.67 × 10−17 N. Calculate the separation between the particles.

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#### Solution

Mass of the particle, = 1 gm $= \frac{1}{1000} kg$

Let the distance between the two particles be r.
Gravitational force between the particle, F = 6.67 × 10−17 N

Also, $F = \frac{\text{ G m} _1 \text{ m }_2}{r^2}$

Substituting the respective values in the above formula, we get :

$6 . 67 \times {10}^{- 17} = \frac{6 . 67 \times {10}^{- 11} \times \left( 1/1000 \right) \times \left( 1/1000 \right)}{r^2}$

$\Rightarrow r^2 = \frac{6 . 67 \times {10}^{- 6} \times {10}^{- 11}}{6 . 67 \times {10}^{- 17}}$

$= \frac{{10}^{- 17}}{{10}^{- 17}} = 1$

$\Rightarrow r = \sqrt{1} = 1 \text{ m }$

∴ The separation between the particles is 1 m.

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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 4 The Forces
Exercise | Q 1 | Page 63
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