#### Question

The given figure shows two circles with centres A and B; and radii 5 cm and 3 cm respectively, touching each other internally. If the perpendicular bisector of AB meets the bigger circle in P and Q, find the length of PQ.

#### Solution

Join AP and produce AB to meet the bigger circle at C.

AB = AC – BC = 5 cm – 3 cm = 2 cm But, M is the mid – point of AB.

∴ `AM = 2/2 = 1cm`

Now in right ∆APM,

`AP^2 = MP^2 + AM^2` [Pythagoras Theorem]

⇒ ` (5)^2 = MP^2 +1`

⇒ `25 = MP^2 1`

⇒ ` MP^2 = 25 -1`

⇒ `MP^2 = 24`

⇒ ` MP =sqrt24 =sqrt(4 xx 6 )= 2sqrt 6 cm`

∴ `PQ = 2MP = 2xx 2sqrt 6 = 4sqrt 6 cm`

⇒ ` PQ = 4 xx 2.45 = 9.8 cm`

Is there an error in this question or solution?

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The Given Figure Shows Two Circles with Centres a and B; and Radii 5 Cm and 3 Cm Respectively, Touching Each Other Internally. If the Perpendicular Bisector of Ab Meets the Bigger Circle in P and Q, Concept: Chord Properties - the Perpendicular to a Chord from the Center Bisects the Chord (Without Proof).

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