The Frequency Distribution Table Shows the Number of Mango Trees in a Grove and Their Yield of Mangoes. Find the Median of Data. - Algebra

Sum

The frequency distribution table shows the number of mango trees in a grove and their yield of mangoes. Find the median of data.

 No. of Mangoes 50 - 100 100 - 150 150 - 200 200 - 250 250 - 300 No. of trees 33 30 90 80 17

Solution

 Class (Number of working hours) Frequency(Number of workers) Cumulative frequency less than theupper limit 50 - 100 33 33 100 - 150 30 63 150 - 200(Median Class) 90 153 200 - 250 80 233 250 - 300 17 250 N = 250

From the above table, we get

L (Lower class limit of the median class) = 150

N (Sum of frequencies) = 250

h (Class interval of the median class) = 50

f (Frequency of the median class) = 90

cf (Cumulative frequency of the class preceding the median class) = 63

Now, Median = L + ((N/2 - cf)/f) xx h

= 150 + ((250/2 - 63)/90) xx 50

= 150 + ((125 - 63)/90) xx 50

= 150 + (62/9) xx 5

= 150 + 310/9

= 150 + 34.44

= 184.44 mangoes

= 184 mangoes

Hence, the median of data is 184 mangoes.

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Chapter 6: Statistics - Practice Set 6.2 [Page 145]

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Balbharati Maths 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.2 | Q 2 | Page 145

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