# The Four Vertices of a Quadrilateral Are (1, 2), (−5, 6), (7, −4) and (K, −2) Taken in Order. If the Area of the Quadrilateral is Zero, Find the Value Of K - Mathematics

The four vertices of a quadrilateral are (1, 2), (−5, 6), (7, −4) and (k, −2) taken in order. If the area of the quadrilateral is zero, find the value of k.

#### Solution

GIVEN: The four vertices of quadrilateral are (1, 2), (−5, 6), (7, −4) and D (k, −2) taken in order. If the area of the quadrilateral is zero

TO FIND: value of k

PROOF: Let four vertices of quadrilateral are A (1, 2) and B (−5, 6) and C (7, −4) and D (k, −2)

We know area of triangle formed by three points   (x1, y1),(x2, y2) and (x3, y3)is given by

Δ =1/2[x_1(y_2 -y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]

Δ=1/2[x_1y_2+x_2y_3+x_3y_3)]

NOW AREA OF ΔABC

Taking three point when A(1,2) and B (-5,6) and C (7,-4)

Area (ΔABC)

=1/2[{6+20+14}-{-10+42-4}

=1/2[{40}-{28}]

=1/2[{12}]

Area (ΔABC) =6 sq.units

Also,

Now Area of ΔACD

Taking three points when A (1, 2) and C (7, −4) and D (k, −2)

=1/2[{-4-14+2k}-{14-4k-2}

=1/2[{2k-18}-{12-4k}

=1/2[{6k-30}]

=[{3k-15}]

Hence

Area (ABCD) = Area (ΔABC) + Area (ΔACD)

0=6+3k-15 (substituting the value )

k=3

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Exercise 6.5 | Q 3 | Page 53