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The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. Find the length of the ladder.

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#### Solution

Let the length of the ladder be x m.

In right angled ΔABC,

AC^{2} = AB^{2} + BC^{2} ......[By Pythagoras theorem]

⇒ (x)^{2} = (8)^{2} + (6)^{2}

⇒ `sqrt((8)^2 + (6)^2)` = `sqrt(64 + 36)` = `sqrt(100)`

⇒ x = 10 m

Hence, the length of the ladder is 10 m.

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