Sum
The following table shows the classification of number of vehicles and their speeds on Mumbai-Pune express way. Find the median of the data.
Average Speed of
Vehicles(Km/hr) |
60 - 64 | 64 - 69 | 70 - 74 | 75 - 79 | 79 - 84 | 84 - 89 |
No. of vehicles | 10 | 34 | 55 | 85 | 10 | 6 |
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Solution
Class
(Number of working hours) |
Continuous
classes |
Frequency (Number of workers) |
Cumulaive frequency less than the upper limit |
60 - 64 | 59.5 - 64.5 | 10 | 10 |
64 - 69 | 64.5 - 69.5 | 34 | 44 |
70 - 74 | 69.5 - 74.5 | 55 | 99 → cf |
75 - 79 | 74.5 - 79.5 | 85 → f | 184 |
79 - 84 | 79.5 - 84.5 | 10 | 194 |
84 - 89 | 84.5 - 89.5 | 6 | 200 |
Total | - | N = 200 | - |
Here, total frequency = ∑fi = N = 200
∴ `"N"/2 = 200/2 = 100`
Cumulative frequency which is just greater than (or equal) to 100 is 184.
∴ The median class is 74.5 – 79.5.
Now, L = 74.5, f = 85, cf = 99, h = 5
Now, Median = \[L + \left( \frac{\frac{N}{2} - cf}{f} \right) \times h\]\
`= 74.5 + ((100 - 99)/85) xx 5`
= 74.5 + 0.059
= 74.559 ≈ 75
∴ The median of the given data is 75 km/hr (approx.).
Concept: Tabulation of Data
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