# The Following Table Gives the Information of Frequency Distribution of Weekly Wages of 150 Workers of a Company. Find the Mean of the Weekly Wages by 'Step Deviation' Method. - Algebra

Sum

The following table gives the information of frequency distribution of weekly wages of 150 workers of a company. Find the mean of the weekly wages by 'step deviation' method.

 Weekly wages (Rupees) 1000 - 2000 2000 - 3000 3000 - 4000 4000 - 5000 No. of workers 25 45 50 30

#### Solution

 Class (Weekly wages rupees) Class Mark(xi) di = xi − A = xi − 2500 ui = "d"_"i"/"g" = "d"_"i"/1000 Frequency(Number of workers)(fi) Frequency × deviation(fi × ui) 1000 - 2000 1500 −1000 −1 25 −25 2000 - 3000 2500 →A 0 0 45 0 3000 - 4000 3500 1000 1 50 50 4000 - 5000 4500 2000 2 30 60 ∑fi = 150 ∑fiui = 85

Required Mean = (∑"f"_"i""u"_"i")/(∑"f"_"i")

= 85/150

= 0.57
Mean = (barX) = "A" + bar("u")"g"
= 2500 + 0.57 (1000)
= 2500 + 570
​= Rs 3070
Hence, the mean of the weekly wages is Rs 3070.

Is there an error in this question or solution?
Chapter 6: Statistics - Practice Set 6.1 [Page 138]

#### APPEARS IN

Balbharati Maths 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 6 | Page 138

Share