The Following Table Gives the Information of Frequency Distribution of Weekly Wages of 150 Workers of a Company. Find the Mean of the Weekly Wages by 'Step Deviation' Method. - Algebra

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The following table gives the information of frequency distribution of weekly wages of 150 workers of a company. Find the mean of the weekly wages by 'step deviation' method.

Weekly wages (Rupees)
1000 - 2000 2000 - 3000 3000 - 4000 4000 - 5000
No. of workers 25 45 50 30
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Solution

Class
(Weekly wages rupees)
Class Mark
(xi)

di = xi − A

= xi − 2500

ui = `"d"_"i"/"g"`
= `"d"_"i"/1000`
Frequency
(Number of workers)
(fi)
Frequency × deviation
(fi × ui)
1000 - 2000  1500 −1000 −1 25 −25
2000 - 3000  2500 →A 0 0 45 0
3000 - 4000  3500 1000 1 50 50
4000 - 5000  4500 2000 2 30 60
        ∑fi = 150 ∑fiui = 85

Required Mean = `(∑"f"_"i""u"_"i")/(∑"f"_"i")`

= `85/150`

= 0.57
Mean = `(barX) = "A" + bar("u")"g"`
= 2500 + 0.57 (1000)
= 2500 + 570 
​= Rs 3070
Hence, the mean of the weekly wages is Rs 3070.

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Chapter 6: Statistics - Practice Set 6.1 [Page 138]

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Balbharati Maths 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 6 | Page 138

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