# The following is the p.d.f. (ProbabiIity Density Function) of a continuous random variable X : f(x)=x/32,0 = 0 otherwise - Mathematics and Statistics

The following is the p.d.f. (ProbabiIity Density Function) of a continuous random variable X :

f(x)=x/32,0<x<8

= 0 otherwise

(a) Find the expression for c.d.f. (Cumulative Distribution Function) of X.

(b) Also find its value at x = 0.5 and 9.

#### Solution 1

(a) c.d.f. of a continuous random variable X is given by

F(x)=int_(-oo)^xf(y)dy

In the given density function f(x), range of X starts at '0'.

therefore F(x)=int_0^xf(y)dy=int_0^xy/32dy=[y^2/64]^2=x^2/64

"Thus ",F(x)=x^2/64, AA x in R

(b)  F(0.5) =(0.5)^2/64=1/256

For any value of x ≥ 8, F(x)=1

∴ F(9)=1

#### Solution 2

Given p.d.f

f(x)=x/32,0<x<8

c.d.f. = F(X)=int_0^xf(x)dx

=int_0^x x/32dx

=[x^2/64]_0^x

=X^2/64

"at "x = 0.5

F(X)=F(0.5)=(0.5)^2/64=0.25/64=0.0039

For any value of x greater than 8

F(X)=1

therefore F(9)=1

Concept: Probability Distribution - Probability Density Function (P.D.F.)
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