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# The Following Figure Represents a Solid Consisting of a Right Circular Cylinder with a Hemisphere at One End and a Cone at the Other. this Common Radius is 7 Cm. the Height of the Cylinder and Cone Are Each of 4 Cm. Find the Volume of the Solid - ICSE Class 10 - Mathematics

ConceptArea and Volume of Solids - Cone

#### Question

The following figure represents a solid consisting of a right circular cylinder with a hemisphere at one end and a cone at the other. This common radius is 7 cm. The height of the cylinder and cone are each of 4 cm. Find the volume of the solid.

#### Solution

The volume of solid = Volume of cone + Volume of cylinder + Volume of the hemisphere.

Volume of cone = (pir^2h)/3 = (22xx7xx7xx4)/(7xx3) = 616/3 cm^3

Volume of cylinder = pir^2h = (22xx7xx7xx4)/7 = 616 cm^3

Volume of hemisphere = 2/3pir^3 = (2xx22xx7xx7xx7)/(3xx7)  =2156/3 cm^3

Total volume = 616/3 + 616 + 2156/3 = 1540  cm^3

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#### APPEARS IN

Solution The Following Figure Represents a Solid Consisting of a Right Circular Cylinder with a Hemisphere at One End and a Cone at the Other. this Common Radius is 7 Cm. the Height of the Cylinder and Cone Are Each of 4 Cm. Find the Volume of the Solid Concept: Area and Volume of Solids - Cone.
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