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The following data was obtained for chemical reaction given below at 975 K.
\[\ce{2NO(g) + 2H2(g) -> N2(g) + 2H2O(g)}\]
[NO] | [H_{2}] | Rate | |
Mol L^{-1} | Mol L^{-1} | Mol L^{-1} s^{-1} | |
(1) | 8 × 10^{-5} | 8 × 10^{-5} | 7 × 10^{-9} |
(2) | 24 × 10^{-5} | 8 × 10^{-5} | 2.1 × 10^{-8} |
(3) | 24 × 10^{-5} | 32 × 10^{-5} | 8.4 × 10^{-8} |
The order of the reaction with respect to NO is ______. (Integer answer)
Options
1
5
2
0
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Solution
The order of the reaction with respect to NO is 1.
Explanation:
Let the order of the reaction with respect to NO and H_{2} are x and y respectively. From experiment (1) and (2).
`"R"_2/"R"_1 = (k["NO"]^x ["H"_2]^y)/(k["NO"]^x ["H"_2]^y)`
`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (k[24 xx 10^-5]^x [8 xx 10^-5]^y)/(k[8 xx 10^-5]^x [8 xx 10^-5]^y)`
`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (cancel(k)[24 xx cancel(10^-5)]^x cancel([8 xx 10^-5]^y))/(cancel(k)[8 xx cancel(10^-5)]^x cancel([8 xx 10^-5]^y))`
`therefore (2.1 xx 10^-8)/(7 xx 10^-9) = (24/8)^x`
`therefore (21 xx 10^-9)/(7 xx 10^-9) = (3)^x`
∴ (3)^{1} = (3)^{x}
∴ x = 1
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