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The First Term of an A. P. is 5 and the Common Difference is 4. Complete the Following Activity and Find the Sum of the First 12 Terms of the A. P. - Algebra

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Question

The first term of an A. P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A. P.

a = 5, d = 4, s12 = ?
`s_n = n/2 [ square ]`
`s_12 = 12/2 [10 +square]`
         `= 6 × square  `
         ` =square`

Solution


`s_n = n/2 [ 2a +(n-1)d ]`


`s_12 = 12/2 [10 + 11 xx 4 ]`

         ` =12/2[10+44]`
         `= 6 ×54  `
         ` s_n= 324`

  Is there an error in this question or solution?
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The First Term of an A. P. is 5 and the Common Difference is 4. Complete the Following Activity and Find the Sum of the First 12 Terms of the A. P. Concept: Sum of First n Terms of an AP.
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