Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
Advertisement Remove all ads

The First Overtone Frequency of a Closed Organ Pipe P1 is Equal to the Fundamental Frequency of a Open Organ Pipe P2. - Physics

Sum

The first overtone frequency of a closed organ pipe P1 is equal to the fundamental frequency of a open organ pipe P2. If the length of the pipe P1 is 30 cm, what will be the length of P2?

Advertisement Remove all ads

Solution

Given:
Length of closed organ pipe L1 = 30 cm
Length of open organ pipe L2 = ?
Let \[f_1\] and \[f_2\] be the frequencies of the closed and open organ pipes, respectively.
The first overtone frequency of a closed organ pipe P1 is given by 

\[f_1  = \frac{3v}{4 L_1}\]

where v is the speed of sound in air.
On substituting the respective values, we get :

\[f_1  = \frac{3v}{4 \times 30}\]

Fundamental frequency of an open organ pipe is given by:

\[f_2  = \left( \frac{v}{2 L_2} \right)\]

As per the question,

\[f_1  =  f_2 \] 

\[  \left( \frac{3 \times v}{4 \times 30} \right) = \left( \frac{v}{2 L_2} \right)\] 

\[     \Rightarrow    L_2  = 20  \text { cm }\]

∴ The length of the pipe P2 will be 20 cm.

Concept: Wave Motion
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 16 Sound Waves
Q 42 | Page 355
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×