Question

The first four terms of an AP, whose first term is –2 and the common difference is –2, are ______.

Options

• – 2, 0, 2, 4

• – 2, 4, – 8, 16

• – 2, – 4, – 6, – 8

• – 2, – 4, – 8, –16

Answer 1

The first four terms of an AP, whose first term is –2 and the common difference is –2, are – 2, – 4, – 6, – 8.

Explanation:

First term, a = – 2

Second Term, d = – 2

a_{1 =} a = – 2

We know that the nth term of an AP is

a_{n =} a + (n – 1)d

Where,

a = first term

a_n is n^th term

d is the common difference

Hence, we have,

a_{2 =} a + d = – 2 + (– 2) = – 4

Similarly,

a_{3 =} – 6

a_{4 =} – 8

So the A.P is – 2, – 4, – 6, – 8