MCQ

The figure shows a heavy block kept on a frictionless surface and being pulled by two ropes of equal mass m. At t = 0, the force on the left rope is withdrawn but the force on the right end continues to act. Let F_{1} and F_{2} be the magnitudes of the forces exerted by right rope and the left rope on the block, respectively.

#### Options

F

_{1}_{ }= F_{2}= F for t < 0F

_{1}_{ }= F_{2}= F + mg for t < 0F

_{1}_{ }= F, F_{2}= F for t > 0F

_{1}< F, F_{2}= F for t > 0

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#### Solution

F_{1}_{ }= F_{2} = F, for t < 0

At t < 0, the block is in equilibrium in the horizontal direction.

So, F_{1}_{ }= F_{2} = F

At t > 0, F_{2}_{ }= 0 and F_{1}_{ }= F.

Concept: Newton's Third Law of Motion

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