MCQ
The equation of the line passing through (1, 5) and perpendicular to the line 3x − 5y + 7 = 0 is
Options
5x + 3y − 20 = 0
3x − 5y + 7 = 0
3x − 5y + 6 = 0
5x + 3y + 7 = 0
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Solution
5x + 3y − 20 = 0
A line perpendicular to 3x − 5y + 7 = 0 is given by \[5x + 3y + \lambda = 0\]
This line passes through (1, 5).
\[5 + 15 + \lambda = 0\]
\[ \Rightarrow \lambda = - 20\]
Therefore, the equation of the required line is \[5x + 3y - 20 = 0\]
Concept: Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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