Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11

# The Equation of the Line Passing Through (1, 5) and Perpendicular to the Line 3x − 5y + 7 = 0 is - Mathematics

MCQ

The equation of the line passing through (1, 5) and perpendicular to the line 3x − 5y + 7 = 0 is

#### Options

•  5x + 3y − 20 = 0

• 3x − 5y + 7 = 0

• 3x − 5y + 6 = 0

• 5x + 3y + 7 = 0

#### Solution

5x + 3y − 20 = 0

A line perpendicular to 3x − 5y + 7 = 0 is given by $5x + 3y + \lambda = 0$

This line passes through (1, 5).

$5 + 15 + \lambda = 0$

$\Rightarrow \lambda = - 20$

Therefore, the equation of the required line is $5x + 3y - 20 = 0$

Concept: Straight Lines - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 23 The straight lines
Q 19 | Page 134