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The Electric Field Associated with a Monochromatic Beam is 1.2 × 1015 Times per Second. Find the Maximum Kinetic Energy of the Photoelectrons - Physics

Sum

The electric field associated with a monochromatic beam is 1.2 × 1015 times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)

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Solution

Given :-

Electric field of the monochromatic beam, `E = 1.2 xx 10^15` times per second

Frequency, v = `(1.2 xx 10^15)/2 = 0.6 xx 10^15  "Hz"`

Work function of the metal surface, `phi` = 2.0 eV

From Einstein's photoelectric equation, kinetic energy,

`K = hv - phi_0`

`⇒ K = (6.63 xx 10^-34 xx 0.6 xx 10^15)/(1.6 xx 10^-19) - 2`

`= 0.486  "eV"`

Thus, the maximum kinetic energy of a photon is 0.486 eV.

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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 20 Photoelectric Effect and Wave-Particle Duality
Q 20 | Page 365
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