#### Question

The electric current in an X-ray tube (from the target to the filament) operating at 40 kV is 10 mA. Assume that on an average, 1% of the total kinetic energy of the electron hitting hte target are converted into X-rays.

(a) What is the total power emitted as X-rays and (b) how much heat is produced in the target every second?

#### Solution

Given :

V = 30 KV

i = 10mA

1% of T_{KE} (total kinetic energy) = X-ray

i = ne

or `n = (10^-2)/(1.6 xx 10^-19)`

= `0.625 xx 10^17` (number of electrons)

KE of one electron = eV

= `1.6 xx 10^-19 xx 40 xx 10^3`

= `6.4 xx 10^-15 "J"`

`"T"_("KE") = 0.625 xx 6.4 xx 10^17 xx 10^-15`

= `4 xx 10^2 "J"`

(b) Heat produced in target per second = 400 − 4 = 396 J

Is there an error in this question or solution?

#### APPEARS IN

Solution The Electric Current in an X-ray Tube (From the Target to the Filament) Operating at 40 Kv is 10 Ma. Assume that on an Average, 1% of the Total Kinetic Energy of the Electron Hitting Concept: Electromagnetic Spectrum.