MCQ
The eccentricity of the hyperbola x2 − 4y2 = 1 is
Options
\[\frac{\sqrt{3}}{2}\]
\[\frac{\sqrt{5}}{2}\]
\[\frac{2}{\sqrt{3}}\]
\[\frac{2}{\sqrt{5}}\]
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Solution
\[\frac{\sqrt{5}}{2}\]
The equation of the hyperbola is \[x^2 - 4 y^2 = 1\].
This can be rewritten in the following way:
\[\frac{x^2}{1} - \frac{y^2}{\frac{1}{4}} = 1\]
This is the standard form of a hyperbola, where
\[a^2 = 1 \text { and }b^2 = \frac{1}{4}\]
The value of eccentricity is calculated in the following way:
\[b^2 = a^2 ( e^2 - 1)\]
\[ \Rightarrow \frac{1}{4} = ( e^2 - 1)\]
\[ \Rightarrow e^2 = \frac{5}{4}\]
\[ \Rightarrow e = \frac{\sqrt{5}}{2}\]
Concept: Hyperbola - Eccentricity
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