HSC Arts 12th Board ExamMaharashtra State Board
Share
Notifications

View all notifications

The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t - 2t2. Find its acceleration when the velocity is zero. - HSC Arts 12th Board Exam - Mathematics and Statistics

Login
Create free account


      Forgot password?

Question

The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t — 2t2. Find its acceleration when the velocity is zero.

Solution

`s=5+20t-2t^2`

`v=(ds)/dt =20-4t`

`v=0`

`20-4t=0`

`4t=20`

`t=5`

`a=(dv)/dt=-4 , "which is contatnt"`

Hence, acceleration is -4 when velocity is zero.

 

  Is there an error in this question or solution?

APPEARS IN

 2015-2016 (March) (with solutions)
Question 4.2.2 | 2.00 marks
Solution The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t - 2t2. Find its acceleration when the velocity is zero. Concept: Maxima and Minima in Closed Interval.
S
View in app×