HSC Arts 12th Board ExamMaharashtra State Board
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# The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t - 2t2. Find its acceleration when the velocity is zero. - HSC Arts 12th Board Exam - Mathematics and Statistics

ConceptMaxima and Minima in Closed Interval

#### Question

The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t — 2t2. Find its acceleration when the velocity is zero.

#### Solution

s=5+20t-2t^2

v=(ds)/dt =20-4t

v=0

20-4t=0

4t=20

t=5

a=(dv)/dt=-4 , "which is contatnt"

Hence, acceleration is -4 when velocity is zero.

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#### APPEARS IN

2015-2016 (March) (with solutions)
Question 4.2.2 | 2.00 marks
Solution The displacement 's' of a moving particle at time 't' is given by s = 5 + 20t - 2t2. Find its acceleration when the velocity is zero. Concept: Maxima and Minima in Closed Interval.
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