# The Dining-hall of a Hotel is 75 M Long; 60 M Broad and 16 M High. It Has Five – Doors 4 M by 3 M Each and Four Windows 3 M by 1.6 M Each. Find the Cost of : (I) Papering Its Walls - Mathematics

Sum

The dining-hall of a hotel is 75 m long; 60 m broad and 16 m high. It has five – doors 4 m by 3 m each and four windows 3 m by 1.6 m each. Find the cost of :

(i) papering its walls at the rate of Rs.12 per m2;
(ii) carpetting its floor at the rate of Rs.25 per m2.

#### Solution

Length of the dining hall of a hotel = 75 m

The breadth of the dining hall of a hotel = 60 m

Height of the dining hall of a hotel = 16 m

(i) Area of four walls of the dining hall = 2[L+B) x H = 2(75 + 60) x 16

= 2(135) xx 16

= 270 xx 16

= 4320 m2

Area of one door = 4 xx 3 m2

= 12 m2

Area of 5 doors = 12 xx 5 = 60 m2

Area of one window = 3 xx 1.6 = 4.8m2

Area of 4 window = 4.8 xx 4 = 19.2m2

Area of the walls to be papered

= 4320 - (60 + 19.2)

= 4320 - 79.2

= 4240.8 m2

Cost of papering the walls @ Rs.12 per m2

= 4240.8 xx 12

= Rs. 50889.60

(ii) Area of floor = L × B

= 75 xx 60

= 4500 m2

Cost of carpetting the floor @ Rs. 25 per m2

= 4500 × 25

= Rs. 112500

Is there an error in this question or solution?
Chapter 21: Surface Area, Volume and Capacity - Exercise 21 (B) [Page 241]

#### APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 21 Surface Area, Volume and Capacity
Exercise 21 (B) | Q 5 | Page 241
Share