The dining-hall of a hotel is 75 m long; 60 m broad and 16 m high. It has five – doors 4 m by 3 m each and four windows 3 m by 1.6 m each. Find the cost of :
(i) papering its walls at the rate of Rs.12 per m2;
(ii) carpetting its floor at the rate of Rs.25 per m2.
Solution
Length of the dining hall of a hotel = 75 m
The breadth of the dining hall of a hotel = 60 m
Height of the dining hall of a hotel = 16 m
(i) Area of four walls of the dining hall = 2[L+B) x H = 2(75 + 60) x 16
= `2(135) xx 16`
= `270 xx 16`
= 4320 m2
Area of one door = `4 xx 3` m2
= 12 m2
Area of 5 doors = `12 xx 5 = 60` m2
Area of one window = `3 xx 1.6 = 4.8`m2
Area of 4 window = `4.8 xx 4 = 19.2`m2
Area of the walls to be papered
= 4320 - (60 + 19.2)
= 4320 - 79.2
= 4240.8 m2
Cost of papering the walls @ Rs.12 per m2
= `4240.8 xx 12`
= Rs. 50889.60
(ii) Area of floor = L × B
= `75 xx 60`
= 4500 m2
Cost of carpetting the floor @ Rs. 25 per m2
= 4500 × 25
= Rs. 112500