The dimensions of universal gravitational constant are........................ a. [L1M0T0] b. [L2M1T0] c. [L-1M1T-2] d. [L3M-1T-2]

(d) [L3M-1T-2] `G=(Fr^2)/(Mm)` `therefore[G]=([L^1M^1T^-2][L^2])/([M^2])=[L^3M^-1T^-2]`

The Dimensions of Universal Gravitational Constant Are - Physics

The dimensions of universal gravitational constant are........................

a. [L¹M⁰T⁰]

b. [L²M¹T⁰]

c. [L^-1M¹T^-2]

d. [L³M^-1T^-2]

(d) [L³M^-1T^-2]

`G=(Fr^2)/(Mm)`

`therefore[G]=([L^1M^1T^-2][L^2])/([M^2])=[L^3M^-1T^-2]`

Concept: Newton’s Law of Gravitation

Is there an error in this question or solution?

2014-2015 (March)

Q 1.6 | 1 mark

Notifications