# The Dimensions of a Rectangular Box Are in the Ratio of 2 : 3 : 4 and the Difference Between the Cost Ofcovering It with Sheet of Paper at the Rates of Rs. 8 and Rs. 9.50 per M2 is Rs.1248. - Mathematics

The dimensions of a rectangular box are in the ratio of 2 : 3 : 4 and the difference between the cost ofcovering it with sheet of paper at the rates of Rs. 8 and Rs. 9.50 per m2 is Rs.1248. Find the dimensions of the box.

#### Solution

Let the ratio be x
∴length = 2x
Breath = 3x
Height = 4x
∴Total surface area = 2[lb+bh+hl]

=2[6x^2+12x^2+8x^2]

=52x^2m^2

When cost is at Rs. 9.51 per    m^2

∴Total   cost  of   52x^2m^2=Rs.8xx52x^2

= Rs. 416x^2

And when the cost is at 95 per   m^2

∴Total   cost  of   52x^2m^2=Rs.9.5xx52x^2

=Rs.499x^2

∴"different in cost"= Rs.494x^2-Rs.416x^2

⇒1248=494x^2-416x^2

⇒78x^2=1248

⇒x^2=16

⇒x=4

Concept: Surface Area of a Cuboid
Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 18 Surface Areas and Volume of a Cuboid and Cube
Exercise 18.1 | Q 16 | Page 15

Share