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Numerical

The diameter of zinc atom is 2.6 Å. Calculate

- radius of zinc atom in pm and
- number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length-wise.

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#### Solution

**a)** Radius of zinc atom = `"Diameter"/2`

`= (2.6 Å)/2`

`= 1.3 xx 10^(-10) " m"`

`=130xx10^(-12) " m" = 130 " pm"`

**b)** Length of the arrangement = 1.6 cm

= 1.6 × 10^{-2} m

Diameter of zinc atom = 2.6 × 10^{-10} m

∴ Number of zinc atoms present in the arrangement

`= (1.6xx10^(-2) " m")/(2.6 xx 10^(-10) " m")`

`= 0.6153 xx 10^8 " m"`

`= 6.153xx10^7`

Concept: Atomic Model

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