The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
It is given that,
Length of the diagonal, d = 24 m
Length of the perpendiculars, h1 and h2, from the opposite vertices to the diagonal are h1 = 8 m and h2 = 13 m
Area of the quadrilateral = `1/2 d(h_1 + h_2)`
= `1/2` (24m) x (13m + 8cm)
= `1/2` (24 m)(21 m)
= 252 `m^2`
Thus, the area of the field is 252 m2.
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