The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

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#### Solution

It is given that,

Length of the diagonal, *d *= 24 m

Length of the perpendiculars, *h*_{1} and *h*_{2}, from the opposite vertices to the diagonal are *h*_{1} = 8 m and *h*_{2} = 13 m

Area of the quadrilateral = `1/2 d(h_1 + h_2)`

= `1/2` (24m) x (13m + 8cm)

= `1/2` (24 m)(21 m)

= 252 `m^2`

Thus, the area of the field is 252 m^{2}.

Concept: Area of a General Quadrilateral

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