#### Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

#### Solution

Given:

Diagonal of a quadrilateral shaped field = 24 m

Perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m.

Now, we know:

Area \[= \frac{1}{2} \times d \times ( h_1 + h_2 )\]

∴ Area of the field \[= \frac{1}{2} \times 24 \times (8 + 13)\]

\[ = 12 \times 21\]

\[ = 252 m^2\]

Perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m.

Now, we know:

Area \[= \frac{1}{2} \times d \times ( h_1 + h_2 )\]

∴ Area of the field \[= \frac{1}{2} \times 24 \times (8 + 13)\]

\[ = 12 \times 21\]

\[ = 252 m^2\]

Is there an error in this question or solution?

Solution The Diagonal of a Quadrilateral Shaped Field is 24 M and the Perpendiculars Dropped on It from the Remaining Opposite Vertices Are 8 M and 13 M. Find the Area of the Field. Concept: Area of a General Quadrilateral.