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The Diagonal of a Quadrilateral Shaped Field is 24 M and the Perpendiculars Dropped on It from the Remaining Opposite Vertices Are 8 M and 13 M. Find the Area of the Field. - Mathematics

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ConceptArea of a General Quadrilateral

Question

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Solution


Given: 

Diagonal of a quadrilateral shaped field = 24 m
Perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m.
Now, we know:
Area \[= \frac{1}{2} \times d \times ( h_1 + h_2 )\]
∴  Area of the field \[= \frac{1}{2} \times 24 \times (8 + 13)\]
\[ = 12 \times 21\]
\[ = 252 m^2\]
  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.1 | Q: 10 | Page no. 14
Solution The Diagonal of a Quadrilateral Shaped Field is 24 M and the Perpendiculars Dropped on It from the Remaining Opposite Vertices Are 8 M and 13 M. Find the Area of the Field. Concept: Area of a General Quadrilateral.
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