The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by
Rate = k [CH3OCH3]3/2 .The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., `Rate = k(p_(CH_3OCH_3))^(3/2)`
If the pressure is measured in bar andtime in minutes, then what are the units of rate and rate constants?
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Solution
If pressure is measured in bar and time in minutes, then
Unit of rate = bar min−1
`Rate = k(p_(CH_3OCH_3))^(3/2)`
`=>k = "Rate"/(P_(CH_3OCH_3))^(3/2)`
Therefore, unit of rate constants (k) = `("bar " min^(-1))/"bar"^(3/2)`
`= "bar"^(-1/2) "min"^(-1)`
Concept: Rate of a Chemical Reaction
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