Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by - Chemistry

The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by

Rate = [CH3OCH3]3/2 .The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e., `Rate = k(p_(CH_3OCH_3))^(3/2)` 

If the pressure is measured in bar andtime in minutes, then what are the units of rate and rate constants?

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Solution

If pressure is measured in bar and time in minutes, then

Unit of rate = bar min−1

`Rate = k(p_(CH_3OCH_3))^(3/2)`

`=>k = "Rate"/(P_(CH_3OCH_3))^(3/2)`

Therefore, unit of rate constants (k) = `("bar " min^(-1))/"bar"^(3/2)`

`= "bar"^(-1/2) "min"^(-1)`

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APPEARS IN

NCERT Class 12 Chemistry Textbook
Chapter 4 Chemical Kinetics
Q 4 | Page 117
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