#### Question

The currents flowing in the two coils of self-inductance L_{1} = 16 mH and L_{2} = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of the currents ?

#### Solution

Power, \[P = IV\]

\[\frac{I_1}{I_2} = \frac{V_2}{V_1} \left( \text { as P } \text { is same } \right)\]

\[ \Rightarrow \frac{I_1}{I_2} = \frac{3}{4}\]

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Solution The Currents Flowing in the Two Coils of Self-inductance L1 = 16 Mh and L2 = 12 Mh Are Increasing at the Same Rate. If the Power Supplied to the Two Coil is Equal, Find the Ratio of the Currents ? Concept: Inductance - Self-Inductance.