#### Question

The current flowing through an inductor of self-inductance L is continuously increasing. Plot a graph showing the variation of

Induced emf versus dI/dt

#### Solution

Induced emf,

`e=(dphi)/dt=-d/dt(LI)`

i.e `e=-L(dI)/dt`

Is there an error in this question or solution?

Solution The Current Flowing Through an Inductor of Self Inductance L is Continuously Increasing. Plot a Graph Showing the Variation of Induced Emf Versus di/dt Concept: Induced Emf and Current.