#### Question

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm^{−1}. Calculate its molar conductivity.

#### Solution

Given,

*κ* = 0.0248 S cm^{−1}

c = 0.20 M

∴ Molar conductivity, `Lambda_m = (kxx1000)/c`

= `(0.0248xx1000)/0.2`

= 124 Scm^{2}mol^{−1}

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Solution The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm^(−1). Calculate its molar conductivity. Concept: Conductance of Electrolytic Solutions - Measurement of the Conductivity of Ionic Solutions.