Sum
The compound interest on Rs 1800 at 10% per annum for a certain period of time is Rs 378. Find the time in years.
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Solution
\[CI = P \left( 1 + \frac{R}{100} \right)^n - P\]
\[ \Rightarrow 378 = 1, 800 \left( 1 + \frac{10}{100} \right)^n - 1, 800\]
\[1, 800 \left( 1 + \frac{10}{100} \right)^n = 2, 178\]
\[ \left( 1 + \frac{10}{100} \right)^n = \frac{2, 178}{1, 800}\]
\[ \left( 1 . 1 \right)^n = 1 . 21\]
\[ \left( 1 . 1 \right)^n = \left( 1 . 1 \right)^2 \]
On comparing both the sides, we get:
n = 2
Thus, the required time is two years .
Is there an error in this question or solution?
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