Question

The combined resistance of a galvanometer of resistance 500Ω and its shunt is 21Ω. Calculate the value of shunt.

Answer 1

Here, G = 500Ω and Req = 21Ω

`1/R_(eq)=1/G+1/S`

`therefore 1/S=1/R_(eq)-1/G=(G-R_(eq))/(GxxR_(eq)`

`therefore S=(GxxR_(eq))/(G-R_(eq)`

`therefore S=(500xx21)/(500-21)=10500/479`

`therefore S= 21.92 Omega`